One person buys 6 roses and 4 carnations for $22. Another person buys 10 roses and 2 carnations for $32. How much do each rose and each carnation cost? Please explain how you got the answer
Let us assume the price of one rose =x and one carnations = y
6x + 4y =22 and 10x + 2y = 32
Now find the value of x from both the equations
6x+4y= 22
6x = 22 – 4y
x = (22-4y)/6
on solving 10x + 2y = 32
10x = 32 – 2y
x= (32 – 2y)/10
Now put both value of x for equivalent and find out the value of y
(22-4y)/6= (32 – 2y)/10
(22-4y)*10 = (32 – 2y)*6
220 – 40y = 192 – 12y
-40y + 12y = 192 – 220
-28y = – 28
y = 1
Now put the value of y in any of the above equation
x = (32 – 2y)/10
x = (32 – 2)/10 ( Put y=1)
x= 30/10
x= 3
The cost of one rose is $3 and the cost of one carnation is $1
One person buys 6 roses and 4 carnations for $22. Another person buys 10 roses and 2 carnations for $32. How much do each rose and each carnation cost? Please explain how you got the answer